Question

The parallel sides of a trapezium are in the ratio 3:4 and the perpendicular distance between them is 12 cm. If the area of a trapezium is 630 cm ², then find the length of shorter side​

Answer 1

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so formula for area of trapezium(A) = x sum of parallel sides(S) x perpendicular distance between parallel sides (P)

so here S = 4x + 3x cm = 7x cm

A = 630 cm²

P = 12 cm

so 630 = x 7x x 12

⇒ x = 630*2/7*12

⇒ 3x = 45 cm ANSWER

Answer 2

Let the lengths of the parallel sides of the trapezium be 3adm and 4adm

Area of a trapezium =

2

1

×(Sumofparallelsides)×height

=>

2

1

×(3a+4a)×9dm=126dm

2

=>

2

1

×7a×9=126

=>a=4

Hence, the lengths of the parallel sides of the trapezium are 3a=12dm and 4a=16dm

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