Question

The parallel sides of a trapezium are in the ratio 4:3 and the perpendicular distance between them is 12cm. It the area of the trapezium is 630 cm2 , then its shorter of the parallel side is :

Answer 1

Hiii
Here is ur answer
Let the parallel sides be 4x and 3x
Area of trapezium = 1/2 (sum of parallel side) ×height
630 cm sq =1/2 (4x+3x) × 12cm
630 cm sq = 1/2 ×7x ×12 cm
630 cm sq = 42 x cm
630 cm sq/42 cm =x
15 cm = x
therefore 4x = 4×15 cm =60 cm
3x = 3×15 cm = 45 cm
So,the shorter parallel side is 45 cm

Hope it will help u

Answer 2

Answer:

60 cm and 45 cm

Shorter parallel side = 45 cm

Step-by-step explanation:

Let the parallel sides of a trapezium be 4x and 3x respectively.

Area of trapezium = 630 cm²

According to the question ;

Area of trapezium = $\frac{1}{2}$ * (sum of || sides ) * h

⇒ Area of trapezium = $\frac{1}{2}$* (4x + 3x) * 12

⇒ 630  = 6 ( 4x + 3x )

⇒ 7x = 630 / 6

⇒ 7x = 105

⇒ x = 105 / 7

⇒ x = 15

Therefore, parallel sides are ;

4x = 4 * 15 = 60 cm

3x = 3 * 15 = 45 cm