Math, asked by shambhavi1634, 5 months ago

the parallel sides of a trapezium are in the ratio 6:7 and distance between them is 12.5 cm.find the lengths of sides if area is 6.50 m^2.​

Answers

Answered by rahibirla001
1

Answer:

4800 cm and 5600 cm

Step-by-step explanation:

Let the parallel sides of a trapezium be 6x and 7x respectively.

Area of trapezium = 6.50 m² = 65000 cm²

According to the question ;

Area of trapezium = \frac{1}{2}

2

1

* (sum of || sides ) * h

⇒ Area of trapezium = \frac{1}{2}

2

1

* (6x + 7x) * 12.5

⇒ 65000 cm² = 12.5 ( 13x ) / 2

⇒ 12.5 * 13x = 65000 * 2

⇒ 13x = 130,000 / 12.5

⇒ 13x = 10,400

⇒ x = 10,400 / 13

⇒ x = 800

Therefore, parallel sides are ;

6x = 6 * 800 = 4800 cm

7x = 7 * 800 = 5600 cm

Answered by itzheatless
3

Answer:-

4800 cm and 5600 cm

Step-by-step explanation:

Let the parallel sides of a trapezium be 6x and 7x respectively.

Area of trapezium = 6.50 m² = 65000 cm²

According to the question ;

Area of trapezium = \frac{1}{2}

2

1

* (sum of || sides ) * h

⇒ Area of trapezium = \frac{1}{2}

2

1

* (6x + 7x) * 12.5

⇒ 65000 cm² = 12.5 ( 13x ) / 2

⇒ 12.5 * 13x = 65000 * 2

⇒ 13x = 130,000 / 12.5

⇒ 13x = 10,400

⇒ x = 10,400 / 13

⇒ x = 800

Therefore, parallel sides are ;

6x = 6 * 800 = 4800 cm

7x = 7 * 800 = 5600 cm

Similar questions
Math, 10 months ago