Question

the parallel sides of a trapezium are in the ratio 6:7 and distance between them is 12.5 cm.find the lengths of sides if area is 6.50 m^2.

Answer 1

hey!!!

given the parallel sides of the trapezium are in ratio 6 : 7

let the parallel sides be 6x and 7x

height of the trapezium = 12.5cm

area of the trapezium is given = 6.50 = 65000cm²
therefore 1/2 × h ( b1 + b2 ) = 65000cm²
>> 1/2 × 12.5 ( 6x + 7x ) = 65000cm²
>> 6.25 × 13x = 65000cm²
>> 13x = 65000/6.25
>> 13x = 10400
>> x = 10400/13
>> x = 800

hence, parallel sides of the trapezium are :-

6x = 6 × 800 = 4800cm

7x = 7 × 8 = 5600cm

cheers!!!

Answer 2

Answer:

4800 cm and 5600 cm

Step-by-step explanation:

Let the parallel sides of a trapezium be 6x and 7x respectively.

Area of trapezium = 6.50 m² = 65000 cm²

According to the question ;

Area of trapezium = $\frac{1}{2}$ * (sum of || sides ) * h

⇒ Area of trapezium = $\frac{1}{2}$ * (6x + 7x) * 12.5

⇒ 65000 cm² = 12.5 ( 13x ) / 2

⇒ 12.5 * 13x = 65000 * 2

⇒ 13x = 130,000 / 12.5

⇒ 13x = 10,400

⇒ x = 10,400 / 13

⇒ x = 800

Therefore, parallel sides are ;

6x = 6 * 800 = 4800 cm

7x = 7 * 800 = 5600 cm