the parallel sides of a trapezium is 120 cm and140 cm and non parallel sides are 50 cm and 52 cm find the area of the trapezium
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In trapezium ABCD
join BD..
Now in ∆ABD and ∆CDB,
sideAB =sideCD
angle ABD = angle CDB
sideBD = sideBD
∆ABC congruent to ∆CDB.... by SAS
ar(∆ABC) =are(∆CDB)..... 1
Now in ∆ABC,
by angle sum property,
AB+BD+AD= 180°
120+BD+50=180°
BD=180-170
BD=10 cm
ar(∆ABC) = 10 cm^2
from 1,
ar(∆ABC) =ar(∆CDB)
ar(∆CDB) =10cm^2
trapezium ABCD= 10+10
=20cm^2
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