The parallel sides of a Trapezium is 77 M and 60 M and its non parallel sides are 26 m and 25 m. find the area of trapezium
Answers
Answered by
13
AB=60 cm;DF=77 cm;AD=25cm; BF=26cmwe calculate the CF:CF=DF-CD=77-60=17 cm
For ΔBCF,we calculate the perimeter of triangleP=BC+BF+CF=25+26+17=68 cmwe calculate the semiperimeter of the triangle:p=P/2=68/2=34cmwe use the formula of Heron:At=√p×(p-BC)×(p-BF)×(p-CF);=√34(34-25)(34-26)(34-17)=√34×9×8×17=√41616= 204 cm²we calculate the height of triangle:BE=2At:CF=(2×204):17=408:17=24 cm
we calculate the area of TrapeziumA =[(AB+DF)×BE):2=[(60+77)×24]=(137×24):2=3288:2=1644 cm²
For ΔBCF,we calculate the perimeter of triangleP=BC+BF+CF=25+26+17=68 cmwe calculate the semiperimeter of the triangle:p=P/2=68/2=34cmwe use the formula of Heron:At=√p×(p-BC)×(p-BF)×(p-CF);=√34(34-25)(34-26)(34-17)=√34×9×8×17=√41616= 204 cm²we calculate the height of triangle:BE=2At:CF=(2×204):17=408:17=24 cm
we calculate the area of TrapeziumA =[(AB+DF)×BE):2=[(60+77)×24]=(137×24):2=3288:2=1644 cm²
Answered by
28
I hope it can help you So please mark as brainliest
Attachments:
Similar questions