Question

The parallel sides of a trapezium is 9 cm and 7 cm and its area is 80 cm. find the altitude

Answer it step by step, and don't Spam ​

Answer 1

Answer:

A=a+b/2×h

Solving forh

h=2A/a+b=2·80/9+7=10cm

Answer 2

Answer:

Given:

1st parallel side=9cm

2nd parallel side=7cm

$Area=80 {cm}^{2}$

Formula used:

$Area \: \: of \: \: trapezium= \frac{1}{2} \times (a + b) \times h$

where a and b are the parallel sides

Solution:

$\frac{1}{2} \times (9cm + 7cm) \times h = 80 {cm}^{2}$

$\frac{1}{2} \times 16cm \times h = 80 {cm}^{2}$

$8cm \times h = 80 {cm}^{2}$

$h = \frac{80 {cm}^{2} }{8cm}$

$h = 10cm$

Therefore,

Altitude(height)=10cm