Question

The parallel sides of a Trapezium is a ratio 3 and 4 and the perpendicular distance between them is 12 centimetre if the area of trapezium is 630 CM square then the shorter of The parallel side is​

Answer 1

Answer:

Let the parallel sides be 3x and 4x.

Area of trapezium = 630cm²

= (1/2)(a+b)×h=630

=(1/2)(3x+4x)×12=630

=(1/2)×7x×12=630

=7x=(630×2)/12

=x=(630×2)/(12×7)

=x=15

Now, the parallel sides are 3×15=45cm

and 4×15=60cm

Thus, the shorter parallel side is 45cm