Question

The parallel sides of a trapezium measure 10cm and 22 cm calculate its area if the distance between the parallel lines is 12 cm​

Answer 1

☞ Question :-

The parallel sides of a trapezium measure 10 cm and 22 cm. Calculate it's area if the distance between the parallel lines is 12 cm.

☞ Given :-

• Parallel lines are in a trapezium
• Sides of trapezium i.e., 10cm & 22cm

☞ To find :-

• Area of trapezium

☞ Solution :-

Refer the diagram :-

$\setlength{\unitlength}{1.2cm}\begin{picture}(8,2)\thicklines\put(8.6,3){\large{A}}\put(7.7,0.9){\large{B}}\put(10,0.7){\sf{\large{22 cm}}}\put(10,3.1){\sf{\large{10 cm}}}\put(13.1,0.9){\large{C}}\put(11.8,0.7){\large{M}}\put(8,1){\line(1,0){5}}\put(12,1){\line(0,2){2}}\put(9,3){\line(3,0){3}}\put(11,1.8){\sf{\large{12 cm}}}\put(13,1){\line(-1,2){1}}\put(8,1){\line(1,2){1}}\put(12.1,3){\large{D}}\end{picture}$

Area of trapezium = 1/2 × perpendicular distance between parallel sides × Sum of parallel sides

➵ ½ × 12 × (10 + 22)

➵ ½ × 12 × 32

➵ 12 × 16

➵ 192 cm²

∴ The area of the trapezium = 192 cm²

Answer 2

Step-by-step explanation:

area of trapezium= 1/2 ×sum of parellal side×distance between them

=> 1/2×10+22×12

=> 1/2×32×12

=> 192cm²

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