Question

the parallel sides of a trapezium measure 12 cm and 20 cm . calculate its area if the distance between the parallel lines is 15 cm the area of the trapezium is
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Answer 1

Answer:

The area of the trapezium is 240 cm^2

Step-by-step explanation:

Parrallel sides of the trapezium = 12 and 20 cm

Height = 15 cm

Now area of the required trapezium,

$= > \frac{1}{2} \times (sum \: of \: parrallel \: sides) \times height$

$= > \frac{1}{2} \times (20 + 12) \times 15 = 240 \: {cm}^{2}$

So the area of the required trapezium is 240 cm^2

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Answer 2

Given:

The parallel sides of a trapezium measure 12 cm and 20 cm. The distance between the parallel lines is 15 cm.

To find:

The area of the trapezium.

Solution:

As we know that in a trapezium having p1 and p2 two parallel sides and 'd' is the distance between two parallel sides, then the area of a trapezium is given by:

$area = \frac{1}{2} (p1 + p2)(d)$

Now,

as given, we have,

The measure of two parallel sides of a trapezium

= 12 cm and 20 cm

So,

the sum of its parallel sides = 12 + 20 = 32 cm

The distance between two parallel sides of a trapezium = 15 cm.

So, its area is

$= \frac{1}{2} \times (32) \times \times 15$

$= 16 \times 15$

$= 240 {cm}^{2}$

Hence, the area of a trapezium is 240 square centimetres.