Question

The parallel sides of a trapezium measure 12 cm and 20 cm. Calculate its area if the distance between the parallel lines is 15 cm.​

Answer 1

Answer:

The area of the trapezium is 240 cm^2

Step-by-step explanation:

Parrallel sides of the trapezium = 12 and 20 cm

Height = 15 cm

Now area of the required trapezium,

= > \frac{1}{2} \times (sum \: of \: parrallel \: sides) \times height=>

2

1

×(sumofparrallelsides)×height

= > \frac{1}{2} \times (20 + 12) \times 15 = 240 \: {cm}^{2}=>

2

1

×(20+12)×15=240cm

2

So the area of the required trapezium is 240 cm^2

Answer 2

Correct Question-:

• The parallel sides of a trapezium measure 12 cm and 20 cm. Calculate its area if the distance between the parallel lines is 15 cm.

AnswEr -:

• $\underline{\boxed{\star{\sf{\purple{Area\:of \:Trapezium \:: \: 240cm².}}}}}$

Explanation-:

Given-:

• The parallel sides of a trapezium measure 12 cm and 20 cm.
• Distance between parallel sides or height of Trapezium is 15 cm .

☆ Figure of Trapezium-:

$\setlength{\unitlength}{1.2 cm}\begin{picture}(0,0)\linethickness{0.5mm}\qbezier(0,0)(0,0)(1,3)\qbezier(5,0)(5,0)(4,3)\qbezier(1,3)(1,3)(4,3)\qbezier(3,0)(8.2,0)(0,0)\put(-0.5,-0.3){ \sf A }\put(5.3,-0.3){ \sf B }\put(4.2,3.1){ \sf C }\put(0.6,3.1){ \sf D }\end{picture}$

To Find -:

• Area of Trapezium.

Now ,

• $\underline{\boxed{\star{\sf{\purple{Area\:of \:Trapezium \::\frac {1}{2} \times Height \times (a+b)\:or \: Sum\:of\:parallel\:sides.}}}}}$

Here ,

• (a + b) or Sum of parallel sides = (12 + 20 )
• Height of Trapezium = 15 cm

Now ,

• $\implies{\sf{\large { Area_{(Trapezium)} = \frac {1}{2} \times 15 \times (12 +20)}}}$
• $\implies{\sf{\large { Area_{(Trapezium)} = \frac {1}{2} \times 15 \times 32}}}$
• $\implies{\sf{\large { Area_{(Trapezium)} = 15 \times 16}}}$
• $\implies{\sf{\large { Area_{(Trapezium)} = 240cm²}}}$

Hence ,

• $\underline{\boxed{\star{\sf{\purple{Area\:of \:Trapezium \:: \: 240cm².}}}}}$

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