Question

the parallel sides of a Trepizium are of measure 20 m and 16 m and the distance between them is 12 m. find its area​

Answer 1

Given :-

• The parallel sides of a Trapezium are of measure 20 m and 16 m and the distance between them is 12 m.

To find :-

• Area of trapezium

Solution :-

• Parallel sides of trapezium = 20m and 16m

• Distance between parallel sides = 12m

As we know that

→ Area of trapezium = ½ (a + b) × h

Where (a + b) is sum of parallel sides and " h " is distance between parallel sides.

• According to question

→ Area of trapezium

→ ½ (a + b) × h

• Put the values

→ ½ × (20 + 16) × 12

→ ½ × 36 × 12

→ 36 × 6

→ 216 m²

Hence,

• Area of trapezium is 216 m²

Answer 2

Given:

• The parallel sides = 20m and 16m
• The distance between them = 12m

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Need to find:

• The area =?

━━━━━━━━━━━━━━━

Solution:

• Let one of the parallel sides be a
• Another side be b
• And the distance between them be = height = h

━━━━━━━━━━━━━

Now

• a= 20m
• b= 16m
• h= 12m

We know,

Area of a trapizium = $\dfrac{sum \: of \: the \: length \: of \: parallel \: sides}{2} \times height$

Also given by,

$Area = \dfrac{a + b}{2} \times h$

Substituting values we get,

$\implies \: area = \dfrac{20 + 16}{2} \times 12$

$\implies \: Area = \dfrac{36}{2} \times 12 \: {m}^{2}$

$\red{\bold{\boxed{\large{\implies \: area = 216 {m}^{2} }}}}$