Question

The parallel sides of an isosceles trapezium are 8 cm and 4 cm long and non parallel sides are 5cm long . what is its area

Answer 1

Answer:

29.16 cm^2

Step-by-step explanation:

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Answer 2

Answer:

The Area of isosceles Trapezium is 30 sq cm

Step-by-step explanation:

Given as :

ABCD is a isosceles Trapezium

The measure of parallel sides of an isosceles Trapezium are

AB = 8 cm ,

CD = 4 cm

The measure non-parallel sides = AD = BC = 5 cm

Let The Area of isosceles Trapezium = A sq cm

According to question

Area of isosceles Trapezium = $\dfrac{1}{2}$ × (sum of parallel sides) × height

Or, Area of isosceles Trapezium = $\dfrac{1}{2}$ × ( AB + CD ) × AD

or, A = $\dfrac{1}{2}$ × ( 8 cm + 4 cm ) × 5 cm

Or A = $\dfrac{1}{2}$ × ( 12 cm ) × 5 cm

∴  A  = $\dfrac{1}{2}$ × 60 cm²

i.e A = 30 sq cm

Or, Area of isosceles Trapezium = 30 sq cm

Hence, The Area of isosceles Trapezium is 30 sq cm . Answer