the parallel sides of an isosceles trapezium are in the ratio 2:3. If its be height is 4cm and area is 60cm2,find the perimeter
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if ratio is 2:3
then sides must be 2x and3x
area of trapezium is 1/2×height×(sum of paralel sides)
so area is 1/2 ×4×(2x+3x)
= 2×(5x)
=10x
acc to ques it is 60cm
10x=60
x=60/10
x=6
acc to it parameters are
2x
=2(6)
=12cm
3x
=3(6)
=18cm
so sides are 12cm and 18cm
then sides must be 2x and3x
area of trapezium is 1/2×height×(sum of paralel sides)
so area is 1/2 ×4×(2x+3x)
= 2×(5x)
=10x
acc to ques it is 60cm
10x=60
x=60/10
x=6
acc to it parameters are
2x
=2(6)
=12cm
3x
=3(6)
=18cm
so sides are 12cm and 18cm
kirtinamisha:
well,thank u so much but u need to find out perimeter also
then use formulae
i am unable to find formulae
may be answer is like sum if all sides 4+4+12+18 which is equal to 38
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