The parallel sides of the trapezium are 10cm and 12cm and one of its non parallel side is 13cm. find the are of trapezium?
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Given:The parallel sides of the trapezium are 10cm and 12cm and one of its non parallel side is 13cm.
If we draw the diagram,
10cm
B ______________ C
l l\
l l \ 13cm
l h l \
l_____________ l___\ D
A E
12cm
AE=BC (parallel to each other and so, equal)
AD=AE+ED
12= 10+ED
ED=2cm..
By applying pythagoras theorem,
we get,
h²+2²=13²
h²+4=169
h²= 169-4
h²=165
h=√165
h=12.85cm
Area of Trapezium =
=
=
=141.35cm²
Given:The parallel sides of the trapezium are 10cm and 12cm and one of its non parallel side is 13cm.
If we draw the diagram,
10cm
B ______________ C
l l\
l l \ 13cm
l h l \
l_____________ l___\ D
A E
12cm
AE=BC (parallel to each other and so, equal)
AD=AE+ED
12= 10+ED
ED=2cm..
By applying pythagoras theorem,
we get,
h²+2²=13²
h²+4=169
h²= 169-4
h²=165
h=√165
h=12.85cm
Area of Trapezium =
=
=
=141.35cm²
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