Question

the parallel sides of trapezium are 20m and 30m and its non parallel sides are 6m and 8m.Find the area of trapeziu

Answer 1

let h is the height of trapezium
so,
6^2=h^2+x^2
8^2=h^2+(10-x)^2


64-36=(10-x)^2- x^2
28=(10-x-x) 10
2.8=10-2x
7.2 = 2x
x=3.6 m

and 10-3.6 =6.4 m

now,
h={6^2-(3.6)^2}^1/2=4.8 m

now,
area of trapezium=1/2 (20+30) x 4.8
=2.4 x 50=120 m^2

Answer 2

Answer:let h is the height of trapezium

so,

6^2=h^2+x^2

8^2=h^2+(10-x)^2

64-36=(10-x)^2- x^2

28=(10-x-x) 10

2.8=10-2x

7.2 = 2x

x=3.6 m

and 10-3.6 =6.4 m

now,

h={6^2-(3.6)^2}^1/2=4.8 m

now,

area of trapezium=1/2 (20+30) x 4.8

=2.4 x 50=120 m^2

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Step-by-step explanation: