the parallel sides of trapezium are 25 cm and 13 cm ,its non parallel sides are equal each being 10 cm . find the area of the trapezium.
Answers
Answered by
11
Answer:
1/2.(38×8) = 152 cm^2. Answer
Step-by-step explanation:
ABCD is a trapezium in which AB = 25 cm , CD= 13cm ( AB | | CD ) , and
BC=AD = 10 cm. , draw perpendiculars CP and DQ from C and D on AB.
PB = QA as BC = AD. =10 cm. Let PB =QA = x cm.
AB = QA+QP+PB. , putting AB=25 cm., PB= QA=x cm. , and QP = CD=13 cm.
25= x +13+x. => 2x= 25–13 =>. x=12/2= 6 cm.
In right angled triangle CPB , CP^2+PB^2 = BC^2.
or. CP^2 + 6^2 = 10^2.
or. CP^2 = 100 -36 =64.
or. CP = 8 cm.
Area of trapezium ABCD = 1/2.(AB+CD)×CP = 1/2.(25+13)×8. cm^2.
= 1/2.(38×8) = 152 cm^2. Answer.
Similar questions