The parallel sides of trapezium are in ratio 3:4 if the distance between the parallel side is 9 cm and its area is 126 cm² find the length of its parallel sides
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Ratio = 3:4
Let the common multiple be x. So, the parallel sides are 4x and 3x
Height = 9 cm
Area = 126 cm²
Area of trapezium = 1/2 × (Sum of parallel sides × h
126 = 1/2 × (4x+3x) × 9
126 × 2/9 = 7x
28 = 7x
x = 28/7 = 4 cm
Length of parallel sides >
3x = 3(4) = 12 cm
4x = 4(4) = 16 cm
Let the common multiple be x. So, the parallel sides are 4x and 3x
Height = 9 cm
Area = 126 cm²
Area of trapezium = 1/2 × (Sum of parallel sides × h
126 = 1/2 × (4x+3x) × 9
126 × 2/9 = 7x
28 = 7x
x = 28/7 = 4 cm
Length of parallel sides >
3x = 3(4) = 12 cm
4x = 4(4) = 16 cm
Divyankasc:
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Let the parallel sides be 3x and 4x
area of trapezium=(sum of parallel sides/2 )*h
(3x+4x/2)*9=126
(7x/2)9=126
63x/2=126
x=(126*2)/63=4
hence the sides are 3x=3*4=12cm
and 4x=4*4=16cm
area of trapezium=(sum of parallel sides/2 )*h
(3x+4x/2)*9=126
(7x/2)9=126
63x/2=126
x=(126*2)/63=4
hence the sides are 3x=3*4=12cm
and 4x=4*4=16cm
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