Question

The parallelogram ABCD and triangle APB are on the same base AB and between the same parallels AB and CD. If ar(ABCD) =30cm² then ar (APB)​

Answer 1

Step-by-step explanation:

Given: Parallelogram ABCD and rectangle ABEF are on same base and have equal areas.

AB=CD ...opposite side of parallelogram

AB=EF ...opposite side of rectangle

and, ∠F=∠E=90

∘

AD>AF and BC>BE ....(Hypotenuse of right angle is greater than other sides )

Now,

Perimeter of □ABCD=AB+BC+CD+DA

Perimeter of □ABEF=AB+BE+EF+FA

• Since, CD=EF and AD>AF,BC>BE
• Perimeter of parallelogram ABCD> Perimeter of rectangle ABEF