Question

the parameter of an isosceles triangle is 32 cm. that ratio of the equal to the base is 3:2 find area of the triangle​

Answer 1

Answer:

The perimeter of an isosceles △=32cm .

Given that the ratio of the equal side to its base is 3:2.

So the ratio of all three sides of the isosceles △=3:3:2

Sum of the ratios = 3+3+2=8

Length of equal side =

8

3

×32=3×4=12

Length of the base =

8

2

×32=2×4=8

According to Heron's formula, Area of an isosceles △ with equal sides a & base b

=

4

1

×b×

(4a

2

−b

2

)

∴ Area of the given isosceles triangle, where a=12 & b=8

=

4

1

×8×

(4×12

2

)−8

2

=2×

(4×144)−64

= 2×

576−64

= 2×

512

=2×

2×16×16

=2×16×

2

= 32

2

∴m=2

Answered By

toppr

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