Question

The parameter of the rectangle is 152m. the width is 22m less than the length. find the length and width

Answer 1

parameter =152m
length= Xm
width= X-22m
perameter of rectangle= 2(l+w)
152m = 2{X + (x-22)}
152m = 2( X+ X -22)
152m = 2(2X -22)
152m = 4x -44
add 44 on opposite side
152m +44 = 4x
196m =4x
divide 4 on opposite side
196/4 =X
49m = X

length=X=49m
width= x-22 = 49-22= 27m
IN ORDER TO CHECK THE ANSWER,
since rectangle has 2 lengths and two widths so 49+49+27+27= 152m which is the perimeter.

hope I helped :)