Question

The parametric equations of the line passing through (3,2) and having inclination 135° is​

Answer 1

Answer:

hope you got your answer

Answer 2

Concept:

The parametric equations of the line are the components of the vector equation and are in the form of, (y - y₁) = m(x - x₁).

Given:

The line passing through (3,2) and having an inclination of 135°.

Find:

We are asked to find the parametric equation.

Solution:

We have,

x₁= 3  and   y₁= 2,

And, Θ=135° i.e. m = tan135°

tan135°= tan(90+45)= (-Cot45°)

So,

(y - y₁) = m(x - x₁)

Substituting values,

(y - 2) = (-Cot45°)(x - 3)

(y - 2) = (-1)(x - 3)

(y - 2) = (- x + 3)

y+x=5

Hence, the parametric equation of the line is y+x=5.

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