The parimeter of two similar triangles are 36cm and 24cm. If the shortest side of the second triangle is 5cm long. Find the length of the shortest side of the first triangle.
Answers
Answer:
7.5cm
Step-by-step explanation:
let the shortest side be x
=p1/p2=s1/s2
=36/24=x/5cm
=3/2×5cm=x
therefore ,x=3/2×5cm
=15/2cm
=7.5cm
so the shortest side =x=7.5cm
Given : perimeter of two similar triangles are 36cm and 24cm.
shortest side of the second triangle is 5cm long
To Find : length of the shortest side of the first triangle.
Solution:
in similar triangles
Ratio of corresponding sides = ratio of perimeter of triangle
=> (shortest side of 1st triangle)/ shortest side of 2nd triangle = perimeter of 1st Triangle / perimeter of 2nd triangle
=> (shortest side of 1st triangle)/ 5 = 36/24
=> (shortest side of 1st triangle)/ 5 =3/2
=> shortest side of 1st triangle = 5 x 3/2
=> shortest side of 1st triangle = 15 /2
=> shortest side of 1st triangle = 7.5
length of the shortest side of the first triangle. = 7.5 cm
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