Math, asked by priya446441, 8 months ago

the parrallel sides of a trapezium are 20cm and 13cm. it's non-parallel side are 10 cm each.find the area of trapezium.​

Answers

Answered by SujalParad
0

Step-by-step explanation:

Parallel Sides= a and b

a=20cm

b=13cm

Non Parallel Side(Height)= 13cm

Area of Trapezium = (a+b)×h/2

=(20+13)×13/2

=33×13/2

= 429/2

=214.5

Answered by mahathivelu
0

Answer:

153.45

Step-by-step explanation:

parallel sides of a trapezium are 20cm and 13cm

non- parallel sides are 10cm

Two parallel sides =AB =13cm and DC= 20cm

Non parallel side = AD= BC = 10cm

construction:- draw parallel line to BC

BC=AE=10cm

Draw another line which perpendicular to DC

Now,

AB=EC=13cm

DE=20-13=7cm

as AF is perpendicular to DC it divide DFand FE equally

so, DF= FE =7/2

DF =3.5cm and FE = 3.5cm

AFE triangle and AFD triangle are right angled triangles

triangle AFE

(AF)^2 +(FE)^2 = (AE)^2

(AF)^2+ (3.5)^2 =(10)^2

(AF)^2 +12.25=100

(AF)^2= 10-12.25

(AF)^2 =87.75

af = \sqrt{87.55}

AF= 9.36

height (AF) = 9.3 cm

Area of trapezium = 1/2×(sum of all parallel sides ×height

= 1/2× (13+20)×9.3

= 1/2 × 33 × 9.3

= 33.93 /2

= 306.9/2

= 153.45.......answer

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