Question

the part of integer A and B such that a divided b E equal to -4 write the different value of a and b​

Answer 1

Answer:

ABCDEFGHIJKLMNOPQRSTUVWXYZ

Answer 2

Answer:

Here, a÷b=−3

Here, a÷b=−3⇒a=−3b

Here, a÷b=−3⇒a=−3bPutting some different values to b, we get corresponding values of a such as

Here, a÷b=−3⇒a=−3bPutting some different values to b, we get corresponding values of a such as (i) b=1, then

Here, a÷b=−3⇒a=−3bPutting some different values to b, we get corresponding values of a such as (i) b=1, thena=−3b=−3×1=−3

Here, a÷b=−3⇒a=−3bPutting some different values to b, we get corresponding values of a such as (i) b=1, thena=−3b=−3×1=−3(−3,1)

Here, a÷b=−3⇒a=−3bPutting some different values to b, we get corresponding values of a such as (i) b=1, thena=−3b=−3×1=−3(−3,1)(ii) b=3, then

Here, a÷b=−3⇒a=−3bPutting some different values to b, we get corresponding values of a such as (i) b=1, thena=−3b=−3×1=−3(−3,1)(ii) b=3, thena=−3×3=−9

Here, a÷b=−3⇒a=−3bPutting some different values to b, we get corresponding values of a such as (i) b=1, thena=−3b=−3×1=−3(−3,1)(ii) b=3, thena=−3×3=−9(−9,3) is a pair.

Here, a÷b=−3⇒a=−3bPutting some different values to b, we get corresponding values of a such as (i) b=1, thena=−3b=−3×1=−3(−3,1)(ii) b=3, thena=−3×3=−9(−9,3) is a pair.(iii) b=4, then a=−3×4=−12

Here, a÷b=−3⇒a=−3bPutting some different values to b, we get corresponding values of a such as (i) b=1, thena=−3b=−3×1=−3(−3,1)(ii) b=3, thena=−3×3=−9(−9,3) is a pair.(iii) b=4, then a=−3×4=−12Pair is (−12,4)

Here, a÷b=−3⇒a=−3bPutting some different values to b, we get corresponding values of a such as (i) b=1, thena=−3b=−3×1=−3(−3,1)(ii) b=3, thena=−3×3=−9(−9,3) is a pair.(iii) b=4, then a=−3×4=−12Pair is (−12,4)(iv) b=5, then a=−3×5=−15

Here, a÷b=−3⇒a=−3bPutting some different values to b, we get corresponding values of a such as (i) b=1, thena=−3b=−3×1=−3(−3,1)(ii) b=3, thena=−3×3=−9(−9,3) is a pair.(iii) b=4, then a=−3×4=−12Pair is (−12,4)(iv) b=5, then a=−3×5=−15Pair is (−15,5)

Here, a÷b=−3⇒a=−3bPutting some different values to b, we get corresponding values of a such as (i) b=1, thena=−3b=−3×1=−3(−3,1)(ii) b=3, thena=−3×3=−9(−9,3) is a pair.(iii) b=4, then a=−3×4=−12Pair is (−12,4)(iv) b=5, then a=−3×5=−15Pair is (−15,5)(v) b=6, then a=−3×6=−18

Here, a÷b=−3⇒a=−3bPutting some different values to b, we get corresponding values of a such as (i) b=1, thena=−3b=−3×1=−3(−3,1)(ii) b=3, thena=−3×3=−9(−9,3) is a pair.(iii) b=4, then a=−3×4=−12Pair is (−12,4)(iv) b=5, then a=−3×5=−15Pair is (−15,5)(v) b=6, then a=−3×6=−18Pair is (−18,6)