The partial ionic equation,
Cr2O7^(-2) + 14H+ + 6e- -------> 2Cr^+3 + 7H20
suggests that the equivalent weight of Cr2O7^-2 will be equal to formula weight divided by______.
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Here The oxidation state of chromium is changed from +6 to +3
Cr2O7-2 + 14H+ + 6e- -------> 2Cr+3 + 7H20
According to the reaction for the above change 6 electrons are involved
Therefore the equivalent weight is equal to formula weight/6.
Cr2O7-2 + 14H+ + 6e- -------> 2Cr+3 + 7H20
According to the reaction for the above change 6 electrons are involved
Therefore the equivalent weight is equal to formula weight/6.
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