Question

The partial pressure of hydrogen in a flask containing 2g H2 and 32g SO2 is

Answer 1

The partial pressure of hydrogen in a flask containing 2g $H_2$ and 32g $SO_2$ is 0.67 atm.

Given:

Mass of $H_2$ gas = 2g

Mass of $SO_2$ gas = 32 g

To find:

Partial pressure of Hydrogen in flask containing 2g $H_2$ and 32g $SO_2$ = ?

Formula to be used:

• Partial pressure of gas in mixture = mole fraction of gas x pure pressure

• Mole fraction of gas = $\frac{moles of gas}{total number of moles of gas in mixture}$
• Number of moles = $\frac{Given mass}{Atomic mass}$

Calculation:

Step 1 : Number of moles

Number of moles of $H_2$ = $\frac{Given mass}{Atomic mass}$ = $\frac{2}{2} = 1$

Number of moles of $SO_2 = \frac{Given mass}{Molecular mass} = \frac{32}{64}= 0.5$

Total number of moles = Moles of $H_2$ + Moles of $SO_2$ = 1 + 0.5 = 1.5 moles

Step 2: Mole fraction

Mole fraction of $H_2$ = $\frac{moles of gas}{total number of moles of gas in mixture}$  = $\frac{1}{1.5} = 0.67$

Step 3 : Partial pressure

Partial pressure of $H_2$ in mixture = mole fraction of gas x pure pressure

Partial pressure of $H_2$ in mixture = 0.67 x 1

Partial pressure of $H_2$ in mixture = 0.67 atm.

Conclusion:

The partial pressure of hydrogen in a flask containing 2g $H_2$ and 32g $SO_2$ is 0.67 atm.

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Answer 2

Ans: 2/3rd of total pressure

explanation