Question

The partial pressure of three gases
A, B and C enclosed in a container
are in the ratio 1:2:3. If the
molecular weights of A, B and Care
in the ratio 6:3:2, then the ratio
by weights they are taken in the
container is -​

Answer 1

Answer:

The ratio  by weights they are taken in the  container is 1:1:1.

Explanation:

$p_a:p_b:p_c=1:2:3$

$P\times \chi_a:p\times \chi_b:P\times \chi_c=1:2:3$

$\chi_a:\chi_b:\chi_c=1:2:3$

$\frac{n_a}{n_a+n_b+n_c}:\frac{n_b}{n_a+n_b+n_c}:\frac{n_c}{n_a+n_b+n_c}=1:2:3$

$n_a:n_b:n_c=1:2:3$

$\frac{w_a}{M_a}:\frac{w_b}{M_b}:\frac{w_c}{M_c}=1:2:3$

$\frac{w_a}{M_a}=1$

$\frac{w_b}{M_b}=2$

$\frac{w_c}{M_c}=3$

Given the  molecular weights of A, B and Care in the ratio 6:3:2.

$M_a:M_b:M_c=6:3:2$

$M_a=6x,M_b=3x,M_c=3x$

$\frac{w_a}{6x}=1$

$\frac{w_b}{3x}=2$

$\frac{w_c}{2x}=3$

$w_a:w_b:w_c=6x:6x:6x=1:1:1$

The ratio  by weights they are taken in the  container is 1:1:1.