Question

The partial pressures are found to be A=0.20, B=0.10, C=0,30 and D-0.50atm.Calculate the numerical value of the equilibrium constant Kp?​

Answer 1

The equilibrium reaction is A+2B⇌C+3D.

The expression for the equilibrium constant is K

p

=

[A][B]

2

[C][D]

3

.

Substitute the values of A, B, C and D are in the above expression.

A=0.20;B=0.10;C=0.30 and D=0.50.

K

p

=

(0.2)(0.1)

2

(0.3)(0.5)

3

=18.75.