Question

the particle initially at rest , moves with an acceleration 5 metre per second square for 5 seconds ......find the distance travelled in 4 second and 5 second ​

Answer 1

Explanation:

Kinematics....... =___=

a = 5

t = 5

Let's calculate v first

v = u +at

it was initially at rest

v = 5×5

v = 25 m/s

S = ut +1/2 at^2

S = 1/2 × 5 × 25

S = 64.5 m

Now,

a = 5

t = 4

v = u +at

it was initially at rest

v = 20 m/s

S = ut +1/2 at^2

S = 1/2 ×5 × 16

S = 40 m

Both S are your answer

Hope it helps you!