Question

The particle is uniformly accelerated with an acceleration of 8m/S,² for 5 sec. If it starts from rest,then the displacement of this particle in the last 1 sec will be​

Answer 1

Given that,

The acceleration a=8m/s

2

Initial velocity u=0m/s

We know that,

The displacement in the nth second

=u+a(n−

2

1

)

Now, the displacement in 5th second

=0+8(5−

2

1

)

=36m

Hence, the distance covered by it in fifth second is 36 m