Question

The particle moves along a straight line and its velocity at a distance 'x' from the origin is
$k \sqrt{a { }^{2} - x {}^{2} }$
Then the acceleration of the particle is.?​

Answer 1

Step-by-step explanation:

Given,

Velocity,

v=ka2−x2

dxdv=−a2−x2kx

Acceleration,

a=v×dxdv

=ka2−x2×(−a2−x2kx)

∴a=−k2x

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