Question

The particle moves in a projectile y = 3/4x - 25/16x2 angle = ?

Answer 1

Equation of trajectory of an projectile has been given as follows :

$y = \dfrac{3x}{4} - \dfrac{25 {x}^{2} }{16}$

To find:

Angle of projection ?

Concept:

Projectile is a 2D motion ( in the X axis and Y axis) which can be imagined as to simultaneously offered in linear motions in the two perpendicular co-ordinate axis.

If we solve the 2 displacement equations of the x-axis and the y-axis we can find out the relation between them and it would give us the equation of trajectory.

$\boxed{ \blue{y = x \tan( \theta) - \dfrac{g {x}^{2} }{2 {u}^{2} { \cos}^{2} ( \theta)} }}$

Calculation:

Comparing the 2 equations , we can say that :

$\therefore \: \: \tan( \theta) = \dfrac{3}{4}$

$= > \theta = { \tan}^{ - 1} ( \dfrac{3}{4} )$

$= > \theta = 37 \degree$

So final answer :

Angle of Projection is 37°.