Math, asked by kittykatrivera3396, 29 days ago

The particle of mass geez moving with the velocity 2i^ + j^ +3k^ c/smagnitude of its linear momentun is

Answers

Answered by Anonymous

0

Answer:

m√14

Put value of m (mass) as given in question

Step-by-step explanation:

P= mv=m(2i^+j^+3k^)=2mi^+mj^+3mk^

Since you have not mentioned the mass, I will assume it as m.

|P|= √[(2m)²+m²+(3m)²]

|P|=√[4m²+m²+9m²]

|P|=√14m²

|P|=m√14

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