the particle required to continue the chain process of uranium fission is
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Hi, Yo!
Well, I don't care where did you find or got that but this question bugged me real bad when I was studying. *Oh memories*.
Ok, I don't want you to suffer from that, so, I am here to answer the question!
The answer is *drumrolls* Neutron
Neutron, the neutral particle present in the nucleus of the atom is really important to carry out the fissioning process. Why do you ask?
Well, when the neutron gets ejected from the nucleus, it moves with high velocity which is not good for fission. Hence, the slowed neutrons (slowed my moderators) are useful in removing the neutron from the uranium atom (nucleus to be precise) to form an isotope and the neutron ejected from the stable uranium atom (now isotope) in turn removes neutron from other uranium nucleus (like geometric progression) in the reactor. So, without neutron, you can't possibly be able to continue the fission process. Hence neutron is needed to continue fissioning in uranium
Hope I answered the question. If I didn't though, sorry 'bout that. Ask me and I'll explain again, my fellow curious mind
Well, I don't care where did you find or got that but this question bugged me real bad when I was studying. *Oh memories*.
Ok, I don't want you to suffer from that, so, I am here to answer the question!
The answer is *drumrolls* Neutron
Neutron, the neutral particle present in the nucleus of the atom is really important to carry out the fissioning process. Why do you ask?
Well, when the neutron gets ejected from the nucleus, it moves with high velocity which is not good for fission. Hence, the slowed neutrons (slowed my moderators) are useful in removing the neutron from the uranium atom (nucleus to be precise) to form an isotope and the neutron ejected from the stable uranium atom (now isotope) in turn removes neutron from other uranium nucleus (like geometric progression) in the reactor. So, without neutron, you can't possibly be able to continue the fission process. Hence neutron is needed to continue fissioning in uranium
Hope I answered the question. If I didn't though, sorry 'bout that. Ask me and I'll explain again, my fellow curious mind
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