Question

The particle starts from rest and moves along a straight with the acceleration a = 3(1 - t/2) m/s^2. Find the displacement after it moves 2 seconds.

Answer 1

a=3(1-t/2) m/s²

v=3(t-t²/4) m/s

x=3(t²/2 - t³/12) m
$x=3(\frac{t^2}{2} -\frac{t^3}{12} )$

$x=3(\frac{2^2}{2} -\frac{2^3}{12} )=4 m$

put t= 2 in the above equation

Ans 4m