the particle starts from rest. Its acceleration at any point 't' is (t+3) m/sec sq. Find the distance travelled in 5 sec.
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Answer:
The acceleration becomes zero at the end of t=6s
so the velocity will stop from increasing so the velocity will be maximum at the end of t=6s
now as the velocity in start of the motion was zero so the velocity after t=6s will be just the increase in velocity by
acceleration in these 6s which is given by the area under the a-t graph
the area is
2
1
×base×height=
2
1
×6s×5m/s
2
=15m/s
so maximum velocity is 15m/s
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