Question

the particle starts from rest. Its acceleration at any point 't' is (t+3) m/sec sq. Find the distance travelled in 5 sec.​

Answer 1

Answer:

The acceleration becomes zero at the end of t=6s

so the velocity will stop from increasing so the velocity will be maximum at the end of t=6s

now as the velocity in start of the motion was zero so the velocity after t=6s will be just the increase in velocity by

acceleration in these 6s which is given by the area under the a-t graph

the area is

2

1

×base×height=

2

1

×6s×5m/s

2

=15m/s

so maximum velocity is 15m/s