Question

the particles move over three quarters of a circle of radius 10 M what is the magnitude of distance and displacement

Answer 1

Hey.

Here is the answer.

distance travelled =

3/4 of circular path = 3/4 × circumference

= 3/4 × 2π(10) = 15π = 47.123 m

Displacement = final position- initial position

= hypotenuse of the rt. angled triangle formed by two radius joining initial and final position

= √(10^2 + 10^2) = 10√2 m = 14.14 m

Thanks.