Question

The particular integral of (D(D+1)-3D+4)=e": = logx
a) [(log.x) *x?
b) f(log.x)r!
cog*)***
d) f(log x)***
O OPTION A
OPTION B
OPTION C
OPTION D
Clear selection​

Answer 1

= -x2/4 .cos 2x + ½ 1/(D2+4) cos 2x – 1/(D2+4) x sin 2x

= -x2/8 cos 2x +1/16 x sin 2x

So, y= c1 cos 2x + c2 sin 2x – x2/ 8 cos 2x + 1/16 x sin 2x.

Some Results on Tangents and Normals:

(i) The equation of the tangent at P(x, y) to the curve y= f(x)

is Y – y = dy/dx(X-x)