Math, asked by gosavib194, 2 months ago

the particular integral of the differential equation
 (d^{2} - 5d + 6)y - 24)
is​

Answers

Answered by Anonymous
0

Answer:

A linear differential equation is that in which the dependent variable and its derivatives occur ... Example 2: Solve (D2 – 5D + 6) y = cos 3x.

Answered by pulakmath007
7

SOLUTION

TO DETERMINE

The particular integral of the differential equation

 \displaystyle \sf{( {D}^{2} - 5D + 6)y = 24 }

EVALUATION

Here the given differential equation is

 \displaystyle \sf{( {D}^{2} - 5D + 6)y = 24 }

Now the required particular integral is given by

 \displaystyle \sf{ P.I.=  \frac{1}{ {D}^{2} - 5D + 6}  \:  \: .24 }

 \displaystyle \sf{ =24. \:  \:   \frac{1}{ {D}^{2} - 5D + 6}  \:  \: 1 }

 \displaystyle \sf{ =24. \:  \:   \frac{1}{ {D}^{2} - 5D + 6}  \:  \:  {e}^{0x}  }

 \displaystyle \sf{ =24. \:  \:   \frac{1}{ {0}^{2} - 5 \times 0 + 6}  \:  \:  {e}^{0x}  }

 \displaystyle \sf{ =24. \:  \:   \frac{1}{6}  \:   \times \: 1  }

 \displaystyle \sf{ =4  }

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