Math, asked by shiny1627, 1 year ago

The password is a 5-digit number.The 4th digit is 4 more than the 2nd one.The 3rd digit is 3 less than the 2nd one.The 1st digit is three times the 5th digit.Three pairs of two digits sum up to 11.

Answers

Answered by CoruscatingGarçon
14

Answer:65292

Step-by-step explanation:

As per given conditions, there are three possible combinations for 2nd, 3rd and 4th digits.

They are (3, 0, 7) or (4, 1, 8) or (5, 2, 9)

It is given that there are 3 pairs whose sum is 11.

All possible pairs are-

(2, 9), (3, 8), (4, 7), (5, 6).

Now required number is 5 digit number and it contains 3 pairs

of 11.

So it must not be having 0 and 1 in it. Hence, the only possible combination for 2nd, 3rd and 4th digits is

(5, 2, 9)

Also, 1st digit is thrice the last digit. The possible combinations are (3, 1), (6, 2) and (9, 3), out of which

only (6, 2) with (5, 2, 9) gives 3 pairs of 11.

Hence, the answer is 65292.

Answered by gautamkumar12394
0

Answer:

69252

Step-by-step explanation:

You know there are 4 pair that gives 11 between 0 to 9.

Therefore 0 and 1 is eliminated.

Thats why second equation

3rd = 2nd -3

That mean 0,1 and 2 never be a part of second position because it will give negative number and an eliminated number that is 1.

Thats why number 5 is suitable for 2nd position.

Hence there is three number comes out, that is 925.

Now we have to find 5th and 1st number.

Equation is 5th = 1st * 3

We know there is only two pair

2 and 6

3 and 9

Else will give you two digits numbers. Hence,

More appropriate Answer may be

69252

Right to left.

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