Question

The path difference between two waves meeting at a point is (11/4)λ. The phase difference between the two waves is​

Answer 1

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The path difference between two waves meeting at a point is (11/4)λ. The phase difference between the two waves is 11 π/2 .

Answer 2

Answer:

Between the two waves, there is a phase difference of $\frac{11\pi }{2}$.

Explanation:

Given Data:

The path difference between the two waves is $\frac{11 \lambda}{4}$

To Calculate :

The two waves' phase differences.

Solution:

The path difference and wavelength both determine the phase difference between two waves. We can use the formula:

Phase difference = $\frac{2\pi }{\lambda }$ x path difference

where λ is the wavelength.

Given the path difference is $\frac{11 \lambda}{4}$, we can substitute this into the formula:

Phase difference = $\frac{2\pi }{\lambda } \times\frac{11 \lambda}{4}$

The wavelength cancels out, leaving:

phase difference = $\frac{2\pi }{\lambda } \times\frac{11 \lambda}{4}$

phase difference = $\frac{11\pi }{2}$

Therefore, the phase difference between the two waves is $\frac{11\pi }{2}$.

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