Question

The path length of oscillation of simple pendulum of length 1m is 16cm. Its maximum velocity is (g=π^2 m/s )

a. 2π cm/s
b. 8π cm/s
c. 4 π cm/s
d. 16π cm/s​

Answer 1

b option is correct I think

Answer 2

Given that,

Path length of the pendulum, l = 16 cm

The amplitude of oscillation is 8 cm.

To find,

The maximum velocity

Solution,

Time period of the pendulum is given by :

$T=2\pi \sqrt{\dfrac{l}{g}} \\\\T=2\pi \sqrt{\dfrac{1}{\pi^2}} \\\\T=2\ s$

Maximum velocity of the particle is given by :

$v=A\omega\\\\v=A\times \dfrac{2\pi}{T}\\\\v=8\pi\ cm/s$

So, the maximum velocity of oscillation of simple pendulum is 8π.

learn more,

Simple pendulum

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