The path of 2m broad is to be built outside a square park of side 18 m along its boundary. Find the cost of construction of the path at Rs.178 per
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4
Answer:
Path 2m broad .
So side of outer square= 22m
Area of outer square = side*side
= 22×22= 484 sqr.m.
Area of inner square = 18×18=324 sqr.m.
Area of path= outer area - inner area
= 484 - 324
= 160 sqr m
Cost of construction of path= Rs.178/m^2
=160×178=Rs.28,480
Answered by
2
Answer:
It's a square park of side A = 18 m
Outside the park a 2 m wide path
Including the path big square side B = 18 +4=22m
Area of big square - Area of Park square = B*2 -A^2
= ( B+ A) (B-A ) =(22+18)(22-18)=40×4=160 Sq.m
The cost for laying the path =160 ×178 =28480
If Rs.178/sq.m The cost = Rs.28480
hope it helps you✌️✌️
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