Math, asked by DishaGaminG, 3 months ago

The path of 2m broad is to be built outside a square park of side 18 m along its boundary. Find the cost of construction of the path at Rs.178 per
 {m}^{2}

Answers

Answered by sujatabaliarsingh85
4

Answer:

Path 2m broad .

So side of outer square= 22m

Area of outer square = side*side

= 22×22= 484 sqr.m.

Area of inner square = 18×18=324 sqr.m.

Area of path= outer area - inner area

= 484 - 324

= 160 sqr m

Cost of construction of path= Rs.178/m^2

=160×178=Rs.28,480

Answered by shivam2258
2

Answer:

It's a square park of side A = 18 m

Outside the park a 2 m wide path

Including the path big square side B = 18 +4=22m

Area of big square - Area of Park square = B*2 -A^2

= ( B+ A) (B-A ) =(22+18)(22-18)=40×4=160 Sq.m

The cost for laying the path =160 ×178 =28480

If Rs.178/sq.m The cost = Rs.28480

hope it helps you

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