The path of a rope bridge can be modeled by a quadratic equation h(l) , where h is the height at a point on the bridge relative to the two ends of the bridge and l is the distance from one end of the bridge. One such bridge connects two ends that are 24 meters apart. The lowest point of the bridge is 3 meters lower than the two ends of the bridge.
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Given : bridge connects two ends that are 24 meters apart. The lowest point of the bridge is 3 meters lower than the two ends of the bridge.
To Find : Equation
Solution:
h is the height at a point on the bridge relative to the two ends of the bridge and l is the distance from one end of the bridge
Ler say:
h = al^2 + bl + c
at l = 0 , h = 0
0 = 0 + 0 + c
c = 9
at l.= 24 , h = 0
0 = a(24)^2 + b(24) + 0
b = - 24a
at l = 12 h = -3
-3 = a(12)^2 + b(12) + 0
-3 = 144a - 288a
-3 = -144a
1 = 48a
a = 1/48
b = -1/2
h = l^2/48 - l/2
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