the path of light in different media in shown in the figures
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Answer:
1. sin60×1=(optical density of medium) ×sinr
Optical density of medium=sin60°/sinr
So, higher the angle of refraction, higher the value of sin, and lesser the optical density.
Hence, optical density of medium C is highest.
2. Speed of light in any medium=c/(optical density of medium)
So, lower the optical density, higher the speed of light. Hence, answer is medium A as it has lowest optical density(as inferred from 1)
3. As seen in 1. optical density of medium A is less than that of medium B, light will bend towards the normal as when a Ray travels from medium of lower optical density to a medium of higher optical density, it bends towards the normal.
4. As seen in 1, refractive index of B will be less than that of C.
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Nihal1234567890
Nihal1234567890 Ambitious
This is what I know
1. Higher the angle of refractions, lesser the optical density and vice versa
Since medium c has th loves tangle of refraction it has the maximum optical density.
2. lower the optical density , higher the speed of light . Refer to ‘1.’ .
So medium a will have maximum speed of light
3.light will bend toward the normal
4 we can calculate the refractive index and write this
Refractive index of b is less than the refractive index of
Hope this help
I sorry if there is a mistake
If there is please comment and I will correct it
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