Question

the path of light ray from three different media A,B and C for given angle of incidence is shown in picture.Study the diagram and answer the following question

Answer 1

1. sin60×1=(optical density of medium) ×sinr
Optical density of medium=sin60°/sinr
So, higher the angle of refraction, higher the value of sin, and lesser the optical density.
Hence, optical density of medium C is highest.
2. Speed of light in any medium=c/(optical density of medium)
So, lower the optical density, higher the speed of light. Hence, answer is medium A as it has lowest optical density(as inferred from 1)
3. As seen in 1. optical density of medium A is less than that of medium B, light will bend towards the normal as when a Ray travels from medium of lower optical density to a medium of higher optical density, it bends towards the normal.
4. As seen in 1, refractive index of B will be less than that of C.

Answer 2

This is what I know

1. Higher the angle of refractions, lesser the optical density and vice versa

Since medium c has th loves tangle of refraction it has the maximum optical density.

2. lower the optical density , higher the speed of light . Refer to ‘1.’ .

So medium a will have maximum speed of light

3.light will bend toward the normal

4 we can calculate the refractive index and write this

Refractive index of b is less than the refractive index of

Hope this help

I sorry if there is a mistake

If there is please comment and I will correct it