the path of two trains is given as 2x+4y-4=0 and x+2y+6=0 respectively. represent the path of trains graphically (plz the answer correct and don't play around)
Answers
EXPLANATION.
Graph of the equations.
⇒ 2x + 4y - 4 = 0. - - - - - (1).
⇒ x + 2y + 6 = 0. - - - - - (2).
As we know that,
From equation (1), we get.
⇒ 2x + 4y - 4 = 0. - - - - - (1).
Put the value of x = 0 in the equation, we get.
⇒ 2(0) + 4y - 4 = 0.
⇒ 4y - 4 = 0.
⇒ 4y = 4.
⇒ y = 1.
Their Co-ordinates = (0,1).
Put the value of y = 0 in the equation, we get.
⇒ 2x + 4(0) - 4 = 0.
⇒ 2x - 4 = 0.
⇒ 2x = 4.
⇒ x = 4.
Their Co-ordinates = (4,0).
From equation (2), we get.
⇒ x + 2y + 6 = 0. - - - - - (2).
Put the value of x = 0 in the equation, we get.
⇒ (0) + 2y + 6 = 0.
⇒ 2y + 6 = 0.
⇒ 2y = - 6.
⇒ y = - 3.
Their Co-ordinates = (0,-3).
Put the value of y = 0 in the equation, we get.
⇒ x + 2(0) + 6 = 0.
⇒ x + 6 = 0.
⇒ x = - 6.
Their Co-ordinates = (-6,0).
Both the curves are parallel to each other.
Given :-
2x + 4y - 4 = 0
x + 2y + 6 = 0
To Find :-
Represent graphically
Soution :-
◼ I n E q 1
2x + 4y - 4 = 0
2x + 4y = 4 (i)
Putting x as 0
↠ 2(0) + 4y = 4
↠ 0 + 4y = 4
↠ 4y = 4
↠ y = 4/4
↠ y = 1
Co-ordinate - (0,1)
Putting y as 0
↠ 2x + 4(0) = 4
↠ 2x = 4
↠ x = 4/2
↠ x = 2
Co-ordinate = (2,0)
◼ I n E q 2
x + 2y + 6 = 0
x + 2y = -6
Putting x as 0
↠ 0 + 2y = -6
↠ 2y = -6
↠ y = -6/2
↠ y = -3
Co-ordinate = (0,-3)
Putting y as 0
↠ x + 2(0) = -6
↠ x = -6
Co-ordinate = (-6,0)
