Question

The patient in a hospital is given soup daily in a cylindrical bowl of diameter
7cm. If the bowl is filled with soup to a height of 4cm, how much soup the hospital has to prepare daily to serve 400 patients? (use π = 22/7)​

Answer 1

$\huge \mathfrak \color {green} \underline {\underline {Your\: Question}}$

The patient in a hospital is given soup daily in a cylindrical bowl of diameter 7cm. If the bowl is filled with soup to a height of 4cm, how much soup the hospital has to prepare daily to serve 400 patients? (use π = 22/7)

$\huge \mathfrak \color {green} \underline {\underline {Answer}}$

Diameter of the bowl = 7cm

Radius: 7/2 = 3.5cm

Height: 4cm

Volume of soup in each bowl =

$\pi {r}^{2} h$

Value of π is 22/7, Putting the value in above eqn

=

$\frac{22}{7} \times 3.5 \: cm \times 3.5 \: cm \: \times 4 \: cm$

$= {154 \: cm}^{3}$

The volume of 1 patient is 154 cm³

For 400 patients,

=> 400 × 154 cm³ = 61600 cm³

As 1000 cm³ = 1 litre

61600 cm³ = 61600/1000

= 61.6 litre

The hospital has to prepare 61.6 litre soup to fulfill 400 patients.

Please mark me as BRAINLIEST