the pd across the plates of a condenser is 60 V and it's capacity is 12uf. another condenser of capacitance 24uf is connected in series and its free plate is earthed. then, the of across the 12uf condenser will be?
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Two condensers of capacity 4μF and 6μF are connected in series. A potential difference of 500 volt is applied between the outer plates of the compound capacitor. The numerical value of charge on each condenser will be :
The equivalent capacitance is C
eq
=
4+6
4×6
=
10
24
μC
and Q eq
C
eq
V=
10
24
×500=1200μC
As the capacitors are in series so the charge on each capacitors is equal to the equivalent charge. i.e Q
4
=Q
6
=Q
eq
=1200μC
Explanation:
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1200ùC
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